At a given instant of time the position vector of a particle moving in a circle with a velocity 3 \stackrel{\^}{\bo {i}}-4 \stackrel{\^}{\bo {j}}+5 \stackrel{\^}{\bo {k}} is \stackrel{\^}{\bo {i}}+9 \stackrel{\^}{\bo {j}}-3 \stackrel{\^}{\bo {k}}. Its angular velocity at that time is

Correct Answer is : (13^i−29^j−31^k)146

\stackrel{\^}{(13 {\bo {i}}+29 \stackrel{\^}{\bo {j}}-31 \stackrel{\^}{\bo {k}})}/{\sqrt{146}}

\stackrel{\^}{(13 {\bo {i}}-29 \stackrel{\^}{\bo {j}}-31 \stackrel{\^}{\bo {k}})}/{146}

\stackrel{\^}{(13 {\bo {i}}+29 \stackrel{\^}{\bo {j}}-31 \stackrel{\^}{\bo {k}})}/{\sqrt{146}}

\stackrel{\^}{(13 {\bo {i}}+29 \stackrel{\^}{\bo {j}}+31 \stackrel{\^}{\bo {k}})}/{146}

EAMCET Engineering 2005 Solved Paper

Section: Physics

Question : 2 of 160

Marks: +1, -0

At a given instant of time the position vector of a particle moving in a circle with a velocity 3

−4

−3

. Its angular velocity at that time is

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