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Question : 153 of 160
Marks:
+1,
-0
Solution:
Let
I=‌| 200sin‌x+100‌cos‌x |
| sin‌x+cos‌x |
‌dx =100‌‌| (sin‌x+cos‌x)+sin‌x |
| sin‌x+cos‌x |
‌dx =100[1‌dx+‌‌dx]Let
I1=‌‌dx . . . (i)
=‌| sin‌(−x) |
| sin‌(‌−x)+cos(‌−x) |
‌dx ⇒‌‌I1=‌‌dx . . . (ii)
On adding Eqs. (i) and (ii), we get
‌2I1=1‌dx=‌⇒I1=‌∴‌I=100[‌+‌]=100×‌=75π
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