EAMCET Engineering 2005 Solved Paper

Section: Mathematics

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Question : 136 of 160

Marks: +1, -0

The parabola with directrix x+2y−1=0 and focus (1,0) is

4x2−4xy+y2−8x+4y+4=0
4x2+4xy+y2−8x+4y+4=0
4x2+5xy+y2+8x−4y+4=0
4x2−4xy+y2−8x−4y+4=0

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