EAMCET Engineering 2005 Solved Paper

Let the equation of line which is perpendicular to 5x−2y=7, is
2x+5y=λ . . . (i)
Given lines are
‌2x+3y=1 . . . (ii)
and ‌3x+4y=6 . . . (iii)
On solving Eqs. (ii) and (iii), we get
x=14,y=−9
Since the Eq. (i) is passing through the point (14,−9)
⇒‌2(14)+5(−9)‌=λ
⇒‌28−45‌=λ
⇒λ‌=−17
∴ Equation (i) becomes
2x+5y=−17
or 2x+5y+17=0