If the vector \bo {a}=2 \stackrel{\^}{\bo {i}}+3 \stackrel{\^}{\bo {j}}+6 \stackrel{\^}{\bo {k}} and \bo {b} are collinear and |\bo {b}|=21, then \bo {b} equal to:

Correct Answer is : ±3(2^i+3^j+6^k)

\pm(2 \stackrel{\^}{\bo {i}}+3 \stackrel{\^}{\bo {j}}+6 \stackrel{\^}{\bo {k}})

\pm 3(2 \stackrel{\^}{\bo {i}}+3 \stackrel{\^}{\bo {j}}+6 \stackrel{\^}{\bo {k}})

(\stackrel{\^}{\bo {i}}+\stackrel{\^}{\bo {j}}+\stackrel{\^}{\bo {k}})

\pm 21(2 \stackrel{\^}{\bo {i}}+3 \stackrel{\^}{\bo {j}}+6 \stackrel{\^}{\bo {k}})

EAMCET Engineering 2005 Solved Paper

Section: Mathematics

Question : 115 of 160

Marks: +1, -0

If the vector a=2

and b are collinear and |b|=21, then b equal to:

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