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Question : 109 of 160
Marks:
+1,
-0
Solution:
‌sin‌−1‌+2tan−1‌‌=sin‌−1‌+tan−1‌‌=sin‌−1‌+tan−1‌‌=sin‌−1‌+tan−1‌‌=sin‌−1‌+cos−1‌‌‌[∵tan−1‌=cos−1‌]‌=‌ ‌[∵sin‌−1x+cos−1x=‌]
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