At a given instant of time two particles are having the position vectors 4 \stackrel{\^}{\bo {i}}+4 \stackrel{\^}{\bo {j}}+57 \stackrel{\^}{\bo {k}} metres and 2 \stackrel{\^}{\bo {i}}+2 \stackrel{\^}{\bo {j}}+5 \stackrel{\^}{\bo {k}} respectively. If the velocity of the first particle be 0.4 \stackrel{\^}{\bo {i}} {\ms}^{-1}, the velocity of second particle in metre per second if they collide after 10 { \sec} is

Correct Answer is : 0.6(^i−^j+13^k)

6 (\stackrel{\^}{\bo {i}}-\stackrel{\^}{\bo {j}}+\frac{1}{3} \stackrel{\^}{\bo {k}})

0.6 (\stackrel{\^}{\bo {i}}-\stackrel{\^}{\bo {j}}+\frac{1}{3} \stackrel{\^}{\bo {k}})

6 (\stackrel{\^}{\bo {i}}+\stackrel{\^}{\bo {j}}+\frac{1}{3} \stackrel{\^}{\bo {k}})

0.6 (\stackrel{\^}{\bo {i}}+\stackrel{\^}{\bo {j}}-\frac{1}{3} \stackrel{\^}{\bo {k}})

EAMCET Engineering 2004 Solved Paper

Section: Physics

Question : 2 of 160

Marks: +1, -0

At a given instant of time two particles are having the position vectors 4

+57

metres and 2

respectively. If the velocity of the first particle be 0.4

ms−1, the velocity of second particle in metre per second if they collide after 10 sec is

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