EAMCET Engineering 2004 Solved Paper

Equation of circle is
x2+y2=25 . . . (i)
Polar equation of a circle with respect to the point (1,a) and (b,2) is
x+ay=25 . . . (ii)
bx+2y=25 . . . (iii)
Since, (1,a) and (b,2) are the conjugate point of a circle, therefore point (1,a) satisfy the equation (iii), we get
‌b+2a=25
‌⇒‌‌2b+4a=50
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