Let the equation of any plane passing through P(2,−1,3) is a(x−2)+b(y+1)+c(z−3)=0 Where a,b,c are the direction ratios. Since, point O(0,0,0,) is perpendicular to the foot of the plane at a point P(2,−1,3) ∴‌‌ Direction's of OP=2,−1,3 Since the line OP is perpendicular to the plane, therefore the direction's of the normal to the plane is proportional to the direction is of OP ∴ Required equation of plane is ‌2(x−2)−1(y+1)+3(z−3)=0 ‌⇒‌‌2x−y+3z−14=0