EAMCET Engineering 2004 Solved Paper

Section: Physics

Question : 11 of 160

Marks: +1, -0

The time period of a simple pendulum is T. When the length is increased by 10‌cm, its period is T1. When the length is decreased by 10‌cm, its period is T2. Then, relation between T,T1 and T2 is

‌
2
T2
=‌
1
T12
+‌
1
T22
‌
2
T2
=‌
1
T12
−‌
1
T22
2T2=T12+T22
2T2=T12−T22

Validate

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