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Question : 156 of 160
Marks:
+1,
-0
Solution:
cos‌α‌s‌i‌n‌(β−γ)+cos‌β‌s‌i‌n‌(γ−α)
+cos‌γ‌s‌i‌n‌(α−β)
=cos‌α[sin‌β‌cos‌γ−cos‌β‌s‌i‌n‌γ]
+cos‌β[sin‌γ‌cos‌α−cos‌γ‌s‌i‌n‌α]
+cos‌γ[sin‌α‌cos‌β−cos‌α‌s‌i‌n‌β]=0
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