EAMCET Engineering 2003 Solved Paper

Section: Mathematics

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Question : 142 of 160

Marks: +1, -0

If ‌‌0<y<21∕3 and x(y3−1)=1, then ‌

2

x

+‌

2

3x3

+‌

2

5x5

+... is equal to:

log(‌
y3
2−y3
)
log(‌
y3
1−y3
)
log(‌
2y3
1−y3
)
log(‌
y3
1−2y3
)

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