EAMCET Engineering 2003 Solved Paper

Section: Mathematics
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Question : 134 of 160
 
Marks: +1, -0
If tn=‌
1
4
(n+2)
(n+3)
for n=1,2,3..., then ‌
1
t1
+‌
1
t2
+...
+‌
1
t2003
is equal to
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