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Question : 200 of 200
Marks:
+1,
-0
Solution:
- Given that
∠A=90∘Now,
r2+r3=4R‌cos‌sin‌‌‌cos‌+4R‌cos‌ ‌cos‌sin‌‌‌=4R‌cos‌[sin‌‌‌cos‌+cos‌sin‌‌]‌=4R‌cos‌45∘⋅sin‌(‌)‌=4R⋅‌⋅sin‌(‌−‌)‌=4R⋅‌⋅cos(‌)‌=4R⋅‌⋅cos‌45∘‌=4R⋅‌⋅‌=2R‌∴r2+r3=2R‌‌ Also, ‌‌‌r1+r2+r3−r=4R=2(2R)‌r1+r2+r3−r=2(r2+r3)‌⇒‌‌r2+r3=r1−r‌
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