\int {3^x \dx}/{\sqrt{9^x-1}} is equal to

Correct Answer is : 1log3log3x+√9x−1+c

\frac{1}{\log 3} \log 3^x+\sqrt{9^x-1} +c

\frac{1}{\log 3} \log 3^x-\sqrt{9^x-1} +c

\frac{1}{\log 9} \log 3^x+\sqrt{9^x-1} +c

\frac{1}{\log 3} \log 9^x+\sqrt{9^x-1} +c

EAMCET Engineering 2002 Solved Paper

Section: Mathematics

Question : 153 of 200

Marks: +1, -0

∫‌

3x‌dx

√9x−1

is equal to

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