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Question : 149 of 200
Marks:
+1,
-0
Solution:
We have,
z=‌[sin‌‌+cos(1+‌)] ‌=‌[cos‌⋅‌−sin‌(1+‌)(−‌)]+(−‌)[sin‌‌+cos(1+‌)]x‌=y[‌‌cos‌+‌sin‌(1+‌)]−‌[sin‌‌+cos(1+‌)]⇒‌‌x‌=cos‌+‌sin‌(1+‌)−z . . . (i)
‌ Similarly, ‌‌‌y‌=−cos‌−‌sin‌(1+‌)+z . . . (ii)
On adding Eqs. (i) and (ii)
x‌=−y‌
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