EAMCET Engineering 2002 Solved Paper

Moment of inertial of solid cylinder, about the axis passing through its centre of mass and perpendicular to its planeIXY=M(‌

l2

12

+‌

R2

4

)
From theorem of parallel axis, moment of inertial of cylinder about an axis passing through its edge and perpendicular to it plane.
IAB‌=IXY+M(‌

l

2

)2
∴‌‌IAB‌=M(‌

l2

12

+‌

R2

4

)+M‌

l2

4

‌=M(‌

l2

3

+‌

R2

4

)
But l=6R
∴‌‌IAB‌=M[‌

(6R)2

3

+‌

R2

4

]
‌=M[12R2+‌

R2

4

]
‌=M(‌

49R2

4

)=‌

49MR2

4