© examsiri.com
Question : 199 of 200
Marks:
+1,
-0
Solution:
a2sin‌2C+c2sin‌2A‌=4R2[sin‌2A⋅2sin‌C‌cos‌C.‌+sin‌2C⋅2sin‌A+cos‌A]‌=4R2⋅2sin‌Asin‌C[cos‌C‌s‌i‌n‌A+sin‌C‌cos‌A]‌=8R2sin‌Asin‌Csin‌(A+C) amp;=8R2sin‌Asin‌Bsin‌Camp;=8R2⋅‌⋅‌⋅‌amp;=‌=4∆
© examsiri.com
Go to Question: