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Question : 196 of 200
Marks:
+1,
-0
Solution:
We have,
‌sin‌h−1(‌)=θ‌⇒‌‌‌= sinhθ‌‌ Now, ‌cos‌h2‌θ=1+sin‌2θ‌=1+‌=‌‌∴‌‌cosh‌θ=‌‌⇒‌‌tan‌h‌θ=‌=x‌θ=tan−1x‌⇒‌‌sin‌h−1(‌)=tan−1x‌
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