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Question : 171 of 200
Marks:
+1,
-0
Solution:
We have,
‌(1−x)−1∕2=1+‌x+‌x2‌‌x3+...‌(1−x)−1∕2=1+‌x+‌x2+‌x3+...Put
x=‌(1−‌)−1∕2‌=1+‌+‌+‌+...√2=‌1+‌+‌+‌+...
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