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EAMCET Engineering 2001 Solved Paper
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Section:
Mathematics
© examsiri.com
Question :
151 of 200
Marks:
+1
,
-0
∫
(
x
+
1
)
2
e
x
‌
dx
is equal to
x
e
x
+
C
x
2
x
x
+
C
(
x
+
1
)
e
x
+
C
(
x
2
+
1
)
e
x
+
C
Validate
Solution:
‌
∫
(
x
+
1
)
2
e
x
‌
dx
‌
‌
=
(
x
+
1
)
2
e
x
−
∫
2
(
x
+
1
)
e
x
‌
dx
‌
‌
=
(
x
+
1
)
2
e
x
−
2
(
x
+
1
)
e
x
+
2
e
x
+
C
‌
‌
=
e
x
[
x
2
+
2
x
+
1
−
2
x
−
2
+
2
]
+
C
‌
‌
=
e
x
[
x
2
+
1
]
+
C
© examsiri.com
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