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Question : 144 of 200
Marks:
+1,
-0
Solution:
Let
y=(x−α)(x−β)y‌=x2−(α+β)x+αβy′‌=2x−(α+β)For maximum or minimum, put
y′=0⇒2x−(α+β)=0⇒x=‌⇒y′′=2=+‌ ve ‌ The minimum value at
x=‌ is
y‌=(‌−α)(‌−β)‌=‌(β−α)(α−β)=−‌(α−β)2
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