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Question : 141 of 200
Marks:
+1,
-0
Solution:
‌{sin‌−1.‌(3x−4x3)}‌ Put ‌x‌=sin‌θ⇒‌‌θ‌=sin‌−1x‌=‌{sin‌−1(3sin‌θ−4sin‌3θ)}‌=‌{sin‌−1sin‌3θ}‌=‌{3θ}=3‌sin‌−1x=‌
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