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Question : 103 of 200
Marks:
+1,
-0
Solution:
We have,
a+b‌=(++t)+(+2+3)‌=2+3+(t+3)and
‌‌a−b=(++t)−(+2+3)=−+(t−3)Since,
(a+b) and
(a−b) are perpendicular to each other, then
‌(a+b)⋅(a−b)=0‌⇒‌‌[2+3+(t+3)]⋅[−+(t−3)]=0‌⇒‌‌0−3+t2−9=0‌⇒‌‌0‌‌t=±2√3
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