If y=(6 x^{5}-7 x^{3}+9)^{-1{/}3} then \frac{d y}{d x} is

Correct Answer is : (−13)(6x5−7x3+9)−4/3(30x4−21x2)

(-\frac{1}{3})(6 x^{5}-7 x^{3}+9)^{-4 {/}3}(30 x^{4}-21 x^{2})

(\frac{1}{3})(6 x^{5}-7 x^{3}+9)^{-4{/}3}(30 x^{4}-21 x^{2})

(-\frac{1}{3})(6 x^{5}-7 x^{3}+9)^{4{/}3}(30 x^{4}-21 x^{2})

Differential Calculus

Question : 56 of 69

Marks: +1, -0

y=(6 x^{5}-7 x^{3}+9)^{-1{/}3}

then

\;{d y}/{d x}

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