If y=\sqrt{x^{2}+\sqrt{x^{2}+\sqrt{x^{2}+...........\infty}}} then \frac{d y}{d x} is

Differential Calculus

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y=√{x^{2}+√{x^{2}+√{x^{2}+...........∞}}}

then

\;{d y}/{d x}

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