If f(x)=\log (11 x^{2}+7 x-5) then f'(x) is

Correct Answer is : 22x+711x2+7x−5

\frac{\log (11 x^{2}+7 x-5)}{22 x+7}

\frac{11 x^{2}+7 x-5}{22 x+7-5}

Differential Calculus

Question : 14 of 69

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f(x)=\log (11 x^{2}+7 x-5)

then

f'(x)

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