\frac{111 \times 111 \times 111 + 99 \times 99 \times 99 + 3 \times 111 \times 111 \times 99 + 3 \times 111 \times 99 \times 99}{111 \times 111 + 99 \times 99 + 2 \times 111 \times 99}

Delhi Police Constable Exam Model Paper 3

Question : 77 of 100

Marks: +1, -0

{111 × 111 × 111 + 99 × 99 × 99 + 3 × 111 × 111 × 99 + 3 × 111 × 99 × 99}/{111 × 111 + 99 × 99 + 2 × 111 × 99}

Solution:

GIVEN:

{111 × 111 × 111 + 99 × 99 × 99 + 3 × 111 × 111 × 99 + 3 × 111 × 99 × 99}/{111 × 111 + 99 × 99 + 2 × 111 × 99}

FORMULA USED:

(a + b)^3 = a^3 + b^3 + 3a^2b + 3ab^2

(a + b)^2 = a^2 + b^2 + 2ab

CALCULATION
:Now,
=

{111 × 111 × 111 + 99 × 99 × 99 + 3 × 111 × 111 × 99 + 3 × 111 × 99 × 99}/{111 × 111 + 99 × 99 + 2 × 111 × 99}

{111^3 + 99^3 + 3 × 111^2 × 99 + 3 × 111 × 99^2} /{111^3 + 99^3+ 2 × 111 × 99}

Now,

{(111 + 99) ^3}/{(111 + 99)^ 2}= (111 + 99)

= (111 + 99)

= 210

Go to Question:

Prev Question

Next Question