CUSAT 2022 BTech Solved Paper Shift 4

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Question : 144 of 200

Marks: +1, -0

A common tangent to 9x2−16y2=144 and x2+y2=9 is

y=‌
3x
√7
+‌
15
√7
y=‌
3x
√7
−‌
15
√7
y=3x√‌
2
7
+‌
15
√7
y=3‌
3x
√7
−‌
15
√7

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