Let M=\left(\begin{array}{c}\cos \\\{\pi\end\frac{array}{4} , - \sin \frac{\pi}{4} ; \sin \frac{\pi}{4} , \cos \frac{\pi}{4})} and Y=\left(\begin{array}{c}\\\{1\end{array}/{\sqrt{2}} ; {1}/{\sqrt{2}})}. Then M^3 Y=

\left(\begin{array}{c}-1 \ 0)\end{array}

\left(\begin{array}{c}1 \ 0)\end{array}

\left(\begin{array}{c}\\\{-1\end{array}/{\sqrt{2}} ; {1}/{\sqrt{2}})}