The sides of a parallelogram are \overrightarrow{a}=\overrightarrow{i}+2 \overrightarrow{j}-3 \overrightarrow{k}, \overrightarrow{b}=\overrightarrow{i}+\overrightarrow{j}+2 \overrightarrow{k}. Then the unit vector parallel to one of the diagonals is

Correct Answer is : 1√14(2→i+3→j−→k)

{1}/{\sqrt{14}}(2 \overrightarrow{i}+3 \overrightarrow{j}+\overrightarrow{k})

{1}/{\sqrt{14}}(2 \overrightarrow{i}+3 \overrightarrow{j}-\overrightarrow{k})

{1}/{\sqrt{26}}(\overrightarrow{j}+5 \overrightarrow{k})

\frac{1}{26}(-\overrightarrow{j}-5 \overrightarrow{k})

CUSAT 2021 BTech Solved Paper Shift 3

Question : 244 of 250

Marks: +1, -0

The sides of a parallelogram are

→

−3

→

. Then the unit vector parallel to one of the diagonals is

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