\frac{d}{d x} \{\tan ^{-1} (\frac{3 x-x^3}{1-3 x^2}) \} is equal to

Correct Answer is : 31+x2∀|x|<1√3

\frac{3}{1+9 x^2} \forall{| x|}< {1}/{\sqrt{3}}

\frac{9}{1+x^2} \forall {| x|}< {1}/{\sqrt{3}}

\frac{3}{1+x^2} \forall {| x|}< {1}/{\sqrt{3}}

\frac{1}{9+x^2} \forall {| x|}< {1}/{\sqrt{3}}

CUSAT 2021 BTech Solved Paper Shift 3

Question : 219 of 250

Marks: +1, -0

‌

{tan−1(‌

3x−x3

1−3x2

)} is equal to

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