In a Young's double slit experiment, let {\S}_1 and {\S}_2 be two slits and {\C} be the center of the screen. If angle \angle {\S}_1 {\CS}_2=\theta, and \lambda is the wavelength, the fringe width will be

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In a Young's double slit experiment, let S1 and S2 be two slits and C be the center of the screen. If angle ∠S1CS2=θ, and λ is the wavelength, the fringe width will be

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2λ
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2θ

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