CUSAT 2019 BTech Solved Paper

© examsiri.com

Question : 111 of 250

Marks: +1, -0

In a Poisson distribution, P(X=2)=P(X=3). Given that e−3=0.050. Then P(X=5) is

0.202
0.352
0.125
0.101

Go to Question:

Prev Question

Next Question