If x+\lambda y-2 and x-\mu y+1 are factors of the expression 6 x^2-x y-y^2-6 x+8 y-12, then

Correct Answer is : λ=13,µ=−12

\lambda=\frac{1}{3}, \mu=\frac{1}{2}

\lambda=\frac{1}{3}, \mu=\frac{-1}{2}