If the cube root of unity is 1, \omega, \omega^2, then the roots of the equation (x+1)^3+8=0 are

Correct Answer is : −3,−1−2ω,−1−2ω2

CUSAT 2018 BTech Solved Paper

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If the cube root of unity is 1,ω,ω2, then the roots of the equation (x+1)3+8=0 are

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