Let f:[-1,1] \to {\R} be a function defined as f(x)=\frac{x}{x+2}. The inverse of the function f:[-1,1] \to Range of f is

Correct Answer is : f−1(y)=2y1−y,y≠1

f^{-1}(y)=\frac{2 y}{1-y}, y \neq 1

f^{-1}(y)=\frac{y}{1-y}, y \neq 1

CUSAT 2018 BTech Solved Paper

Question : 3 of 250

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Let f:[−1,1]→R be a function defined as f(x)=‌

x+2

. The inverse of the function f:[−1,1]→ Range of f is

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