If y=f (x^3) , z=g (x^5) , f^{'}(x)=\tan x and g^{'}(x)= \sec x, then the value of \frac{d y}{d x} is

Correct Answer is : 35x2⋅tanx3 secx5

\frac{3}{5 x^2} \cdot \frac{\tan x^3}{ \sec x^5}

\frac{5 x^2}{3} \cdot \frac{ \sec x^5}{\tan x^3}

\frac{3 x^2}{5} \cdot \frac{\tan x^3}{ \sec x^5}

\frac{5}{3 x^2} \frac{\tan x^3}{ \sec x^5}

CUSAT 2018 BTech Solved Paper

Question : 118 of 250

Marks: +1, -0

If y=f(x3),z=g(x5),f′(x)=tan‌x and g′(x)= secx, then the value of ‌

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