For differential equation ye^{\frac{x}{y}}dx = (xe^{\frac{x}{y}} + y^{2}) dy, y(0) = 1, the value of y is equal to:

CUET UG Math 30 Aug 2022 Shift 2

Question : 11 of 50

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For differential equation

ye^{\;{x}/{y}}dx = (xe^{\;{x}/{y}} + y^{2})

dy, y(0) = 1, the value of y is equal to:

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