The value of λ, so that the lines \frac{1−x}{3} = \frac{7y−14}{2\lambda } = \frac{z−3}{2} and \frac{7−7x}{3\lambda } = \frac{y−5}{1} = \frac{6−z}{5} are perpendicular is

CUET UG Math 19 Jun 2023 Paper

Question : 38 of 50

Marks: +1, -0

The value of λ, so that the lines

\;{1−x}/{3} = \;{7y−14}/{2λ\;} = \;{z−3}/{2}

and

\;{7−7x}/{3λ\;} = \;{y−5}/{1} = \;{6−z}/{5}

are perpendicular is

Go to Question:

Prev Question

Next Question