CTET Class I to V 2019 Dec Paper

Question : 61 of 150

Marks: +1, -0

A person boarded an express train on 29th November, 2019 at Surat (Gujarat) for Nagarcoil (Kerala). The train departed from Surat at 19:45 hours and reached Nagarcoil at 11:45 hours on 1st December, 2019. If the distance between Surat and Nagarcoil by train route is nearly 2120 km, the average speed of the train during this journey was

132.5 km/h
60 km/h
53 km/h
45 km/h

Validate

Solution:

Distance = 2120 km
total time taken from 29th November 2019 at 19:45 to 1st December 2019 at 11:45 = 40 hrs
Therefore, the average speed of the train during this journey

= {\Total \Time}/ {\Total \Distance} = 2120/40

= 53 km/h

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