CTET Class I to V 2015 Sep Paper

Question : 65 of 150

Marks: +1, -0

A person boarded an express train on 30th August, 2015 at Ahmedabad for Trivandrum. The train departed from Ahmedabad at 13.30 hours and reached Trivandrum at 7.30 hours on 1st September, 2015. If the distance between Ahmedabad and Trivandrum is 2268 km, the average speed of the train between the two stations was:

42 m/s
15 m/s
9 m/s
54 m/s

Validate

Solution:

Total time between

30^{\;\text "th "\;}

August 2015 to

1^{\;\text "st "\;}

Sep

2015=42 {h}

.
Average speed

=\;{\;\text " Total distance "\;}/{\;\text " Totaltime "\;}

Total distance

=2268 {km}

Total time

=42 {h}

Average speed

=\;{2268 × 1000}/{42 × 60 × 60}=15 {m} \/ {s}

Go to Question:

Prev Question

Next Question