CTET Class I to V 2014 Sep Paper

Option (a) $1\mathrm{cm}=10\mathit{m}\mathit{m}$
$\mathit{S}\mathit{o},\therefore 1\mathit{m}\mathit{m}=\frac{1}{10}\mathit{c}\mathit{m}$
Option (a) is correct.

Option (b) $1\mathit{k}\mathit{g}12\mathrm{grams}=1\mathit{k}\mathit{g}+\frac{12}{1000}\mathit{k}\mathit{g}$
$=1.012\mathit{k}\mathit{g}$
Option (b) is correct.
Option (c)

$=1000\mathit{c}\mathit{m}+10\mathit{c}\mathit{m}$
$=1010\mathit{c}\mathit{m}$
Option (c) is correct.
Option (d)
$\frac{23}{100}=0.23$
So, option (d) is not correct.