CTET Class I to V 2014 Sep Paper

Work done by Gorang on Monday $=4\frac{1}{2}\mathit{h}=\frac{9}{2}\mathit{h}$
Work done by Gorang on Tuesday $=\frac{190}{60}\mathit{h}=\frac{19}{6}\mathit{h}$
Work done by Gorang on Wednesday $=\left(9:10-5:20\right)$
$=3\mathit{h}+\frac{5}{6}\mathit{h}$
$=\frac{23}{6}\mathit{h}$
Work done by Gorang on Friday $=\frac{220}{60}=\frac{11}{3}\mathit{h}$
Total working hours by Gorang
$=\frac{9}{2}\mathit{h}+\frac{19}{6}\mathit{h}+\frac{23}{6}\mathit{h}+\frac{11}{3}\mathit{h}$
$=\frac{\left(27+19+23+22\right)}{6}\mathit{h}=\frac{91}{6}\mathit{h}$
Paid@ $\mathit{₹}42∕\mathit{h}$
So, total amount earn by Gorang from Monday to Friday $=\frac{91}{6}\times 42=\mathit{₹}637$