CTET Class I to V 2012 Jan Paper

Question : 56 of 150

Marks: +1, -0

A suitable approach for explaining that a remainder is always less than the divisor to Class IV students can be

perform lots of division sums on the black-board and show that every time the remainder is less than the divisor
explain verbally to the students, several times
represent division sums as mixed fractions and explain that the numerator of the fraction part is the remainder
grouping of objects in multiples of divisor and showing that the number of objects, not in the group, are less than the divisor

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