CTET 2 Math and Science Sep 2016 Paper

Let r be the radius of the circle.
Since, the perimeter of the circle is $6\mathit{\pi }$
then,$2\mathit{\pi }\mathit{r}=6\mathit{\pi }$
$\mathit{r}=3$
Then, the area of the circle is$=\mathit{\pi }{\mathit{r}}^2=\mathit{\pi }{\left(3\right)}^2=9\mathit{\pi }$
Since, the area of the triangle and the area of the circle are equal.
Then,


height $=\frac{9}{4}\mathit{\pi }$
height $=2.25\mathit{\pi }$
Hence, the required height of the triangle is $2.25\mathit{\pi }$.