CTET 2 Math and Science Sep 2014 Paper

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Question : 46 of 120

Marks: +1, -0

The area of a square is

16/11

of the area of a circle. The ratio of the side of the square to the diameter of the circle is

3 : 1
2 : 1
n : 1
$√2π :1$

Solution:

Area of circle

=πr^2

Diameter of circle

=2×r=2r

Area of a square

=\;\;{16}/{π}×πr^{2}

(\Side)^{2}=16r^{2}

⇒Side

=√{16r^{2}}

Side of square

=4r

\;\;{\;\text"Side of the square"\;}/{\;\text"Diameter of the circle"\;}=\;\;{4r}/{2r}=\;\;{2}/{1}=2:1

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