CTET 2 Math and Science Nov 2012 Paper

Question : 50 of 120

Marks: +1, -0

The area of a rectangle is A

cm^{2}

and length is

l c m

. Its perimeter (in cm) is

Solution:

Area of rectangle

=Acm^2

lb=A

(As 'l' be the length of rectangle)
∴

b=A/l

..........(1)
Perimeter of rectangle

=2(l+b)

=2(l+\;\;{{A}}/{l})

[Putting 'b' value from eqn. (1)]

=2l+{2A}/l

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