CTET 2 Math and Science Nov 2012 Paper

Question : 32 of 120

Marks: +1, -0

In the figure, ABC is a triangle. Measure of ∠ABD, in degrees, is A

Solution:

ADC is a straight line

∴∠{ADC}=180^{∘}

(sum of linear pair)

⇒∠{ADB}+∠{BDC}=180^{∘}

⇒∠ADB+119^{∘}=180^{∘}

∴∠{ADB}=180^{∘}-119^{∘}=61^{∘}

In ΔABD

∠A+∠ABD+∠ADB=180^{∘}

(sum of internal angles of a 'Δ' is 180°

⇒62^{∘}+61^{∘}+∠ADB=180^{∘}

⇒∠ADB=180^{∘}-123^{∘}

∴∠{ADB}=57^{∘}

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