CTET 2 Math and Science Jul 2019 Paper

We have,
10(x + 6) + 8(x – 3) = 5(5x – 4)
10x + 60 + 8x – 24 = 25x – 20
18x + 36 = 25x – 20
7x = 56
x = 8
Now check the options,
(A) 3(3x – 5) = 2x + 1
3(3 × 8 – 5) = 57
2 × 8 + 1 = 17
∴ 3(3x – 5) ≠ 2x + 1
(B) 2(x + 3) = 5(x – 5) + 4
2(8 + 3) = 2 × 11 = 22
5(8 – 5) + 4 = 19
2(x + 3) ≠ 5(x – 5) + 4
(C) 5(x – 5) = 2(x – 3) + 5
5(8 – 5) = 5 × 3 = 15
2(8 – 3) + 5 = 10 + 5 = 15
∴ 5(x – 5) = 2(x – 3) + 5
Hence x value satisfies the option (C) equation.